(158-4x)+(x^2+32)=180

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Solution for (158-4x)+(x^2+32)=180 equation: 



(158-4x)+(x^2+32)=180

We move all terms to the left:

(158-4x)+(x^2+32)-(180)=0

We add all the numbers together, and all the variables

(-4x+158)+(x^2+32)-180=0

We get rid of parentheses

x^2-4x+158+32-180=0

We add all the numbers together, and all the variables

x^2-4x+10=0

a = 1; b = -4; c = +10;
Δ = b2-4ac
Δ = -42-4·1·10
Δ = -24
Delta is less than zero, so there is no solution for the equation

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